Baroque Golden Arabesque Filigree
Royal Baroque gold wire tracery with multi-fold rotational symmetry. Interlocking logarithmic S-scrolls, counter-curling C-volutes, delicate parabolic wire webbing, and gleaming granulated pearl nodes.
60 FPS • Canvas 2D
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Full Executable Algorithm Code
194 lines
6920 chars
// 062 - Baroque Golden Arabesque Filigree (geometry)
// 1:1 Original algorithm engine source
function createBaroqueFiligrane() {
return {
setup() {
},
render(context, timeState, params) {
const { ctx, width, height } = context;
const speed = Number(params.shimmerSpeed ?? 0.6);
const folds = Math.max(3, Math.round(Number(params.folds ?? 8)));
const tightness = Number(params.curlTightness ?? 1.2);
const webDensity = Math.max(3, Math.round(Number(params.webDensity ?? 8)));
const t = timeState.time * speed;
ctx.fillStyle = "#050608";
ctx.fillRect(0, 0, width, height);
const cx = width * 0.5;
const cy = height * 0.5;
const maxR = Math.min(width, height) * 0.44;
ctx.save();
ctx.translate(cx, cy);
const baseHue = 42;
const coreR = maxR * 0.16;
for (let ring = 1; ring <= 3; ring++) {
const rr = ring / 3 * coreR;
ctx.beginPath();
for (let i = 0; i <= folds * 2; i++) {
const a = i / (folds * 2) * Math.PI * 2 + t * (ring % 2 === 0 ? 0.2 : -0.2);
const rMod = rr * (1 + 0.18 * Math.sin(a * folds + t * 2));
const px = Math.cos(a) * rMod;
const py = Math.sin(a) * rMod;
if (i === 0) ctx.moveTo(px, py);
else ctx.lineTo(px, py);
}
ctx.closePath();
ctx.strokeStyle = hsla(baseHue + ring * 5, 90, 72, 0.75);
ctx.lineWidth = 1.4 - ring * 0.2;
ctx.stroke();
}
for (let f = 0; f < folds; f++) {
const baseAngle = f / folds * Math.PI * 2;
ctx.save();
ctx.rotate(baseAngle + t * 0.05);
ctx.beginPath();
const armSteps = 70;
const armPoints = [];
for (let i = 0; i <= armSteps; i++) {
const u = i / armSteps;
const theta = u * Math.PI * 1.8 * tightness;
const r = coreR + (maxR - coreR) * Math.pow(u, 0.88) * (1 + 0.08 * Math.sin(t * 1.5 + f));
const curlOffset = Math.sin(theta) * (maxR * 0.14 * (1 - u) * tightness);
const px = Math.cos(theta * 0.45) * r + curlOffset;
const py = Math.sin(theta * 0.45) * r;
armPoints.push({ x: px, y: py });
if (i === 0) ctx.moveTo(px, py);
else ctx.lineTo(px, py);
}
const shimmer = Math.sin(t * 3 + f * 0.8) * 10;
ctx.strokeStyle = hsla(baseHue + shimmer, 92, 70, 0.85);
ctx.lineWidth = 2;
ctx.stroke();
ctx.beginPath();
const cSteps = 45;
const cPoints = [];
const midAnchor = armPoints[Math.floor(armSteps * 0.52)];
for (let j = 0; j <= cSteps; j++) {
const v = j / cSteps;
const phi = -v * Math.PI * 1.6 * tightness + Math.PI * 0.35;
const cr = maxR * 0.28 * Math.pow(v, 0.9);
const cx_p = midAnchor.x + Math.cos(phi) * cr;
const cy_p = midAnchor.y + Math.sin(phi) * cr;
cPoints.push({ x: cx_p, y: cy_p });
if (j === 0) ctx.moveTo(cx_p, cy_p);
else ctx.lineTo(cx_p, cy_p);
}
ctx.strokeStyle = hsla(baseHue + 8, 85, 76, 0.7);
ctx.lineWidth = 1.3;
ctx.stroke();
for (let w = 1; w <= webDensity; w++) {
const frac = w / (webDensity + 1);
const pA = armPoints[Math.min(armPoints.length - 1, Math.floor(frac * armSteps * 0.85))];
const pB = cPoints[Math.min(cPoints.length - 1, Math.floor((1 - frac) * cSteps))];
ctx.beginPath();
ctx.moveTo(pA.x, pA.y);
const midX = (pA.x + pB.x) * 0.5 + Math.sin(t * 2 + w) * 6;
const midY = (pA.y + pB.y) * 0.5 + Math.cos(t * 2 + w) * 6;
ctx.quadraticCurveTo(midX, midY, pB.x, pB.y);
ctx.strokeStyle = hsla(baseHue - 4 + w % 3 * 6, 80, 78, 0.35);
ctx.lineWidth = 0.75;
ctx.stroke();
}
const tipA = armPoints[armPoints.length - 1];
const tipB = cPoints[cPoints.length - 1];
ctx.fillStyle = hsla(baseHue + 15, 100, 88, 0.95);
ctx.beginPath();
ctx.arc(tipA.x, tipA.y, 3.2, 0, Math.PI * 2);
ctx.fill();
ctx.fillStyle = hsla(baseHue + 20, 100, 95, 0.4);
ctx.beginPath();
ctx.arc(tipA.x, tipA.y, 6, 0, Math.PI * 2);
ctx.fill();
ctx.fillStyle = hsla(baseHue + 10, 95, 84, 0.9);
ctx.beginPath();
ctx.arc(tipB.x, tipB.y, 2.4, 0, Math.PI * 2);
ctx.fill();
for (let b = 1; b <= 4; b++) {
const pt = armPoints[Math.floor(b * 14)];
ctx.fillStyle = hsla(baseHue, 95, 78, 0.75);
ctx.beginPath();
ctx.arc(pt.x, pt.y, 1.5, 0, Math.PI * 2);
ctx.fill();
}
ctx.restore();
}
ctx.beginPath();
const outerSteps = folds * 16;
for (let k = 0; k <= outerSteps; k++) {
const theta = k / outerSteps * Math.PI * 2;
const scallop = Math.abs(Math.sin(theta * (folds * 0.5) + t * 0.2)) * (maxR * 0.08);
const ro = maxR * 0.92 + scallop;
const px = Math.cos(theta) * ro;
const py = Math.sin(theta) * ro;
if (k === 0) ctx.moveTo(px, py);
else ctx.lineTo(px, py);
}
ctx.closePath();
ctx.strokeStyle = hsla(baseHue + 4, 85, 74, 0.45);
ctx.lineWidth = 1;
ctx.stroke();
ctx.restore();
}
};
}
// Default parameters from content metadata
const defaultParams = [
{
"key": "folds",
"label": "Symmetry Folds",
"type": "range",
"min": 4,
"max": 16,
"step": 1,
"defaultValue": 8,
"description": "Radial rotational symmetry order"
},
{
"key": "curlTightness",
"label": "Volute Tightness",
"type": "range",
"min": 0.6,
"max": 2.2,
"step": 0.1,
"defaultValue": 1.2,
"description": "Logarithmic spiral coiling factor"
},
{
"key": "webDensity",
"label": "Lace Web Density",
"type": "range",
"min": 3,
"max": 14,
"step": 1,
"defaultValue": 8,
"description": "Filigree wire infill bridging count"
},
{
"key": "shimmerSpeed",
"label": "Shimmer Speed",
"type": "range",
"min": 0.2,
"max": 2,
"step": 0.1,
"defaultValue": 0.6,
"description": "24K metallic luster cycling rate"
}
];
if (!window.__art_instances) window.__art_instances = {};
if (!window.__art_instances['baroque-filigrane']) {
const inst = typeof createBaroqueFiligrane === 'function' ? createBaroqueFiligrane() : null;
if (inst && inst.setup) {
inst.setup({ ctx, width, height, dpr: 1, aspectRatio: width / height }, defaultParams);
}
window.__art_instances['baroque-filigrane'] = inst;
}
const instance = window.__art_instances['baroque-filigrane'];
if (instance && instance.render) {
instance.render(
{ ctx, width, height, dpr: 1, aspectRatio: width / height },
{ time, deltaTime: dt, frameCount: Math.floor(time * 60), fps: 60 },
defaultParams
);
} Edit in Interactive Playground
Zero Dependencies • Standalone Canvas 2D
ƒ
Mathematical Formulation
high
Analytical Equation
r(θ)=r0ekθ,B(u)=(1−u)2P0+2(1−u)uP1+u2P2,θm=N2πm
Click to expand
∑
Baroque Golden Arabesque Filigree
Full Mathematical System • geometry
100%
Complete System of Equations
[Governing Law][Discrete Progression]theta)⋅r+sin(theta)⋅offset,sin(0.45theta)⋅r][Domain & Space][Parameter State]r(θ)=r0ekθ,B(u)=(1−u)2P0+2(1−u)uP1+u2P2,θm=N2πmr=r0+(R−r0)⋅u0.88,volute=[cos(0.45x∈R2,t∈R+,ω∈[0,2π]λfolds=8(Symmetry Folds),λcurlTightness=1.2(Volute Tightness),λwebDensity=8(Lace Web Density),λshimmerSpeed=0.6(Shimmer Speed)
r(θ)=r0ekθ,B(u)=(1−u)2P0+2(1−u)uP1+u2P2,θm=N2πm
Computational Implementation (JavaScript Engine Equivalent)
r = r_0 + (R-r_0)*u^0.88, volute = [cos(0.45θ)*r + sin(θ)*offset, sin(0.45θ)*r] Compact Formula
r = r_0 + (R-r_0)*u^0.88, volute = [cos(0.45θ)*r + sin(θ)*offset, sin(0.45θ)*r] Mathematical Tags
#filigree
#filigrane
#gold
#baroque
#arabesque
#lace
#jewelry
#ornament
#geometry
Author: Math Art Core Target: 60 FPS
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